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Alex17521 [72]
2 years ago
15

Jeff is responsible for buying supplies of food and medication for the dogs and cats at a local shelter. The food and medication

for a dog cost twice as much as for a cat. He needs to provide supplies for 164 cats and 24 dogs, and his budget is $4,240. How much can he spend on each dog for food and medication?
A. $50

B. $40

C. $30

D. $60

E. $45
Mathematics
1 answer:
NARA [144]2 years ago
4 0
He can spend $40 on each dog for food and medication.
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I need the answer because I can’t i need help
Free_Kalibri [48]

Answer:

3\frac{3}{4} , 4\frac{1}{4} , 4\frac{1}{2} (two x's on this spot), 5

Step-by-step explanation:

you need an x in each point (A, B, C, D, E) given in the chart

notice point B and E are the same

3\frac{3}{4} , 4\frac{1}{4} , 4\frac{1}{2} (two x's on this spot), 5

I believe the bottom left shows the right answer

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3 years ago
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Igoryamba

Answer:

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2 years ago
a salesperson earns a base salary of 74$ per week plus a commission of 4% of sales. if they had 75$ in sales this week what was
Likurg_2 [28]

Answer:

. if ΔJKL is congruent to ΔTUV, which of the following can you NOT conclude as being true? ... equals, minus, 15 Complete the missing value in the solution to the equation. ... salary of 74$ per week plus a commission of 4% of sales. if they had 75$ in ...

Step-by-step explanation:

7 0
2 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
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