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Keith_Richards [23]
3 years ago
5

How many planes exist that pass through points a,b ,and c

Mathematics
2 answers:
shusha [124]3 years ago
6 0

1 because 3 points determine a plane.

3241004551 [841]3 years ago
4 0

Answer:

<h2>only one</h2>

Step-by-step explanation:

<em>There is only one straight line passing through two points.</em>

<em>There is only one plane passing through three points.</em>

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Answer: I think its C

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Step-by-step explanation:

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3 years ago
Emily put $3000.00 in a 2 year CD paying 4% interest compounded monthly. After 2 years she withdrew all her money. What is the a
lakkis [162]

Answer:

A=3244.8 dollars

Step-by-step explanation:

A=p(1+r)^t

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Answer:

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Step-by-step explanation:

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Four water tanks can hold a total of 432.4 gallons of water. On average, how much water can one tank hold? How much water is in
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Read 2 more answers
Given equations A and B as 2/5x+y=12 and 5/2y-x=6 respectively which expression will eliminate the variable X a) 5/2A+2/5B b)5/2
frutty [35]

Answer:

C) A+\frac{2}{5}B

Step-by-step explanation:

Given Equations:

A) \frac{2}{5}x+y=12

B) \frac{5}{2}y-x=6

In order to eliminate x we need to multiply \frac{2}{5} to equation B and add it to A.

Multiplying \frac{2}{5} to B.

⇒ \frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6

⇒ (\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}

⇒ y-\frac{2}{5}x=\frac{12}{5}

Adding it equation A.

   \frac{2}{5}x+y=12

+ -\frac{2}{5}x+y=\frac{12}{5}

We get 2y=\frac{72}{5}

Thus x is eliminated.

So, the expression used to eliminate x is:

A+\frac{2}{5}B

4 0
3 years ago
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