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azamat
3 years ago
7

224% of 320 equal what

Mathematics
1 answer:
Doss [256]3 years ago
3 0
7 hundred sixteen and eight hundredths (aka 716.8)


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-3x = 36 X = ________ can someone answer this plz
koban [17]

Answer:

-12x

Step-by-step explanation:

36÷(-3)= -12

3 0
3 years ago
Read 2 more answers
I need help SOMEONE PLZ HELP ME OUT WITH THIS !! THANK UU
Mama L [17]

Answer:

since they are alternate exteriors, we put a equal sign

2x+78=5x+15

next we subtract 78 on both sides

2x+78-78=5x+15-78

2x=5x-63

then we subtract 5x on both sides

2x-5x=5x-5x-63

-3x=-63

after that we divide -3 on both sides

-3x/-3=-63/-3

and the answer is

x=21

Step-by-step explanation:

8 0
2 years ago
Simplify (3x2-5x-6) - (5x2+4x+4)
Lisa [10]

Answer:

=−2x^2−9x−10

Step-by-step explanation:

would you like an explantion or are you good

8 0
3 years ago
X = -2y + 300 3y = 800 - 4x
devlian [24]

Answer:

<h2>x = 140, y = 80</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x=-2y+300&(1)\\3y=800-4x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\3y=800-4(-2y+300)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3y=800+(-4)(-2y)+(-4)(300)\\\\3y=800+8y-1200\\\\3y=8y-400\qquad\text{subtract}\ 8y\ \text{from both sides}\\\\-5y=-400\qquad\text{divide both sides by (-5)}\\\\y=80\\\\\text{Put it to (1):}\\\\x=-2(80)+300\\\\x=-160+300\\\\x=140

8 0
3 years ago
Read 2 more answers
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

g(-1) = -1

g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

4 0
3 years ago
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