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Basile [38]
3 years ago
8

Solve system of equations

0%3D%208%20%5C%5C%20%20-%202x%20%2B%203y%20-%202z%20%3D%2010" id="TexFormula1" title="x + 2y - z = 4 \\ 2x - y + 3z = 8 \\ - 2x + 3y - 2z = 10" alt="x + 2y - z = 4 \\ 2x - y + 3z = 8 \\ - 2x + 3y - 2z = 10" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Natasha2012 [34]3 years ago
3 0

First, using elimination method for eq. 1 and 2 to eliminate one of the variables.

2x - y + 3z = 8

-2x + 3y - 2z = 10

------------------------------

2y + z = 18

z = 18 - 2y

Now eq. 1 and 3, but multiple eq.1 with 2.

2x + 4y - 2z = 8

-2x + 3y - 2z = 10

----------------------------

7y - 4z = 18

Now you have two new equations 7y -4z = 18 and z = 18 - 2y. Solve for y and z, using substitute method.

7y - 4z = 18

7y - 4(18 - 2y) = 18

7y - 72 + 8y = 18

15y = 18+72

y = 90/15

y = 6

Find z using one of the two new equations.

z = 18 - 2y

z = 18 - 2(6)

z = 18 - 12

z = 6

Now you got y and z, find x using any one of the main three equations.

x + 2y - z = 4

X + 2(6) - 6 = 4

x + 12 - 6 = 4

x = 4 - 6

x = -2

Solutions:

x = -2

y = 6

z = 6

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Answer:

Question 7:

∠L = 124°

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∠T = 98°

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m∠G = 110°

Question 16:

∠G = 60°

Question 17:

∠G = 80°

Question 18:

∠G = 70°

Step-by-step explanation:

The angles can be solving using Symmetry.

Question 7.

The sum of interior angles in an isosceles trapezoid is 360°, and because it is an  isosceles trapezoid

∠K = ∠J  = 118°

∠L = ∠M

∠K+∠J+∠L +∠M = 360°

236° + 2 ∠L = 360°

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∠L = 124°

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∠J = 118°

Question 8.

In a similar fashion,

∠Q+∠T+∠S +∠R = 360°

and

∠R = ∠S = 82°

∠Q = ∠T

∠Q+∠T + 164° = 360°

2∠Q + 164° = 360°

2∠Q = 196°

∠Q = ∠T  =98°.

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∠Q = 98°

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Question 15.

The sum of interior angles of a kite is 360°.

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Because the kite is symmetrical

∠E  = ∠G.

And since all the angles sum to 360°, we have

∠E +∠G + 100° +40° = 360°

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∠E  = 110° = ∠G.

Therefore,

m∠G = 110°

Question 16.

The angles

∠E = ∠G,

and since all the interior angles sum to 360°,

∠E + ∠G + ∠F +∠H = 360°

∠E + ∠G  + 150 + 90 = 360°

∠E + ∠G   = 120 °

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therefore,

∠G = 60°

Question 17.

The shape is a kite; therefore,

∠H = ∠F = 110°

and

∠H + ∠F + ∠E +∠G = 360°

220° + 60° + ∠G = 360°,

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∠G = 80°

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The shape is a kite; therefore,

∠F = ∠H  = 90°

and

∠F +∠H + ∠E + ∠G = 360°

180° + 110° + ∠G  = 360°

therefore,

∠G = 70°.

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