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UkoKoshka [18]
4 years ago
6

HCF of 522, 1624, 1276​

Mathematics
2 answers:
hichkok12 [17]4 years ago
8 0

Answer and Step-by-step explanation:

We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this we~will~have~to~use~prime~factorization.

<u><em>→ Prime factorization of 1624  is :</em></u>

= 2 × 2 × 2 × 7 × 29

<u><em>→ Prime factorisation of 522  is :</em></u><em> </em>

= 2 × 3 × 3 × 29

<u><em>→ Prime factorisation of 1276  is :</em></u><em> </em>

= 2 × 2 × 29 × 11

→ HCF~of~1624 , 522 , 1276~is:<em>  </em>=2× 29=58

sineoko [7]4 years ago
7 0

Answer:

The answer is 2

Step-by-step explanation:

Finding the HCF

2║522║1624║1276

29║261 ║812 ║638

║9 ║28 ║22

There is no common prime number that can divide the numbers above without a remainder.

Therefore, the HCF = 2 × 29 = 58

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