Question

HCF of 522, 1624, 1276​

Answer 1

Answer and Step-by-step explanation:

$We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this$ $we~will~have~to~use~prime~factorization.$

→ Prime factorization of 1624  is :

= 2 × 2 × 2 × 7 × 29

→ Prime factorisation of 522  is :

= 2 × 3 × 3 × 29

→ Prime factorisation of 1276  is :

= 2 × 2 × 29 × 11

→ $HCF~of~1624 , 522 , 1276~is:$  $=2$× $29=58$

Answer 2

Answer:

The answer is 2

Step-by-step explanation:

Finding the HCF

2║522║1624║1276

29║261 ║812 ║638

║9 ║28 ║22

There is no common prime number that can divide the numbers above without a remainder.

Therefore, the HCF = 2 × 29 = 58