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3 years ago

What is the value of x?

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

8 0

180-134=x

x=46

hope this helps :3

cluponka [151]3 years ago

8 0

I think the x= 46.
might have to double check.

**Hope this helps you. Feel free to message me if you have any further questions. (Message me if this answer is right or wrong, please. Thanks.) Hope you have a good day! :) **

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3x + 5y = 7<br> -3x - 2y = -1

Oksanka [162]

Answer:

(-1,2) y=2 x=-1

Step-by-step explanation:

This is a system of equations and in this you see there is 3x and negative three x. To solve this you need tp get rid of one of the variables. so we can add the two equations together to get 3y=6. This means that y=2 if we divide by 3 on both sides. Then we just plug 3 in for y and we get 3x+10=7. We subtract 10 on both sides to get 2x=-3 which means x=-1.

6 0

2 years ago

The boundary lines for the system of inequalities is given in the graph.

diamong [38]

Answer:

region C

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

$\displaystyle y ≤ -x + 2$

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

$\displaystyle y ≥ 2x - 3$

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]

So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.

I am joyous to assist you anytime.

4 0

3 years ago

Read 2 more answers

What is the product? 2 1/3 × 3 1/4

asambeis [7]

Answer:

7.583333 / 7 7/12

Step-by-step explanation:

2 1/3 × 3 1/4

2 1/3=7/3

3 1/4= 13/4

7/3 * 13/4

=91/12

=7 7/12

4 0

3 years ago

Indicate which sets are disjoint to the given set

marysya [2.9K]

If the intersection of two sets is a null set or an empty set, then two sets A and B are disjoint sets. The intersection of a set is therefore empty.

<h3>Explain about the disjoined set?</h3>

Disjoint sets are a pair of sets that do not share any elements. For instance, the sets A=2,3 and B=4,5 are not connected sets. However, set C=3,4,5 and set C=3,6,7 are not disjoint since 3 is a common element in both sets C and D.

Now that we are clear on the disjoint set's definition, let's go on to talking about some more important topics, such the notation and Venn diagram related to it. A B = is the notation used for this particular set. As an illustration, suppose A = 1, 2, 3, and B = 4, 5, 6, 7. A + B = then.

To learn more about disjoined set refer to:

brainly.com/question/28165517

#SPJ1

8 0

1 year ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

2 years ago