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borishaifa [10]
3 years ago
8

Whats an easy way to remember what a subject and predicate means

Mathematics
1 answer:
Naddik [55]3 years ago
5 0
A sentence basically has a subject, the object of the sentence or doer of the action and predicate, the verb, the adjective, etc.
<span>
Sentence structures could be simple (one independent clause), compound (two independent clause with coordinating conjunction), complex (a subordinate & independent clause) and compound-complex sentences (subordinate & two independent clause). These include clauses, conjunctions, coherence and balance and even to the number of words you use in your subject and predicate. The benefit of complex or compound sentences is that it could give you more explanation on the subject or topic of the sentence. This gives you a much more understanding on what the sentence is trying to portray or to message to give.</span>
You might be interested in
A 52-card deck is thoroughly shuffled and you are dealt a hand of 13 cards. (a) If you have at least one ace, what is the probab
jasenka [17]

Answer:

a) 0.371

b) 0.561

Step-by-step explanation:

We can answer both questions using conditional probability.

(a) We need to calculate the probability of obtaining two aces given that you obtained at least one. Let's call <em>A</em> the random variable that determines how many Aces you have. A is a discrete variable that can take any integer value from 0 to 4. We need to calculate

P(A \geq 2 | A \geq 1) = P(A\geq 2 \cap A \geq 1) / P(A \geq 1)

Since having 2 or more aces implies having at least one, the event A \geq 2 \cap A \geq 1 is equal to the event A \geq 2. Therefore, we can rewrite the previous expression as follows

P(A \geq 2) / P(A \geq 1)

We can calculate each of the probabilities by substracting from one the probability of its complementary event, which  are easier to compute

P(A \geq 2) = 1 - P((A \geq 2)^c) = 1 - P((A = 0) \bigsqcup (A = 1)) = 1 - P(A = 0) - P (A = 1)

P (A \geq 1) = 1 - P ((A \geq 1)^c) = 1 - P(A = 0)

We have now to calculate P(A = 0) and P(A = 1).

For the event A = 0, we have to pick 13 cards and obtain no ace at all. Since there are 4 aces on the deck, we need to pick 13 cards from a specific group of 48. The total of favourable cases is equivalent to the ammount of subsets of 13 elements of a set of 48, in other words it is 48 \choose 13. The total of cases is 52 \choose 13. We obtain

P(A = 0) = {48 \choose 13}/{52 \choose 13} = \frac{48! * 39!}{52!*35!} \simeq 0.303  

For the event A = 1, we pick an Ace first, then we pick 12 cards that are no aces. Since we can pick from 4 aces, that would multiply the favourable cases by 4, so we conclude

P(A=1) = 4*{48 \choose 12}/{52 \choose 13} = \frac{4*13*48! * 39!}{52!*36!} \simeq 0.438      

Hence,  

1 - P(A = 1)-P(A=0) /1-P(A=1) = 1 - 0.438 - 0.303/1-0.303 = 0.371

We conclude that the probability of having two aces provided we have one is 0.371

b) For this problem, since we are guaranteed to obtain the ace of spades, we can concentrate on the other 12 cards instead. Those 12 cards have to contain at least one ace (other that the ace of spades).

We can interpret this problem as if we would have removed the ace of spades from the deck and we are dealt 12 cards instead of 13. We need at least one of the 3 remaining aces. We will use the random variable B defined by the amount of aces we have other that the ace of spades. We have to calculate the probability of B being greater or equal than 1. In order to calculate that we can compute the probability of the <em>complementary set</em> and substract that number from 1.

P(B \geq 1) = 1-P(B=0)

In order to calculate P(B=0), we consider the number of favourable cases in which we dont have aces. That number is equal to the amount of subsets of 12 elements from a set with 48 (the deck without aces). Then, the amount of favourable cases is 48 \choose 12. Without the ace of spades, we have 51 cards on the deck, therefore

P(B = 0) = {48 \choose 12} / {51 \choose 12} = \frac{48!*39!}{51!*36!} = 0.438

We can conclude

P(B \geq 1) = 1- 0.438 = 0.561

The probability to obtain at least 2 aces if we have the ace of spades is 0.561

4 0
3 years ago
Nathan opens a new savings account and makes an initial deposit of $400.
AfilCa [17]

Answer:

The answer to the first one is 6

Step-by-step explanation:

If the time frame given is 9 months, then we can find that 9 months is 3/4 of a year. 3/4 x 2% = 0.015.     0.015 x 400 = 6. He would have made 6 dollars in 9 months.

Answer the the second one:

4.5% x 5 (years) = 0.225.     0.225 x 10,000 = 2,250. Since this is a car loan and not a bank interest for example, we add it to the total cost. I'm pretty sure its the third one.

6 0
4 years ago
Harper is a salesperson who sells computers at an electronics store. She makes a base pay amount of $100 per day regardless of s
g100num [7]

Answer:

100x-p*1%

Step-by-step explanation:

5 0
3 years ago
Graph y=x+4 <br> Plz use a graph and show me
Kitty [74]

Answer:

there i graphed it

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the unit rate $1.99 for 30 oz to nearest tenth
KatRina [158]

Answer:

$0.10/oz

Step-by-step explanation:

Unit rate simply means the amount per 1 unit of something.

In this case, we want to find the amount of money for 1 oz of something.

So, we divide 1.99 by 30 and divide 30 by 30 to get:

(1.99 / 30) / (30 / 30) = $0.0663 / 1 oz

Rounded to the nearest tenth, 0.0663 is about 0.1.

Thus, the answer is $0.10/oz.

6 0
3 years ago
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