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zlopas [31]
3 years ago
12

Please help asap!!

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Multiply by the conversion factors that cancel the units you have and give you the units you want.

1200\dfrac{g}{L}\times\dfrac{1\,L}{1000\,mL}\times\dfrac{100\,cg}{1\,g}=\dfrac{1200\cdot 100\,cg}{1000\,mL}\\\\=\bf{120\dfrac{cg}{mL}}

Your best choice is ...

... B. 120 cg/mL

k0ka [10]3 years ago
3 0

Answer:

b.120 cg/mL

Step-by-step explanation:

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The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require more than 15 minutes to grade

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16.3}{4.2}

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62.17% probability that a randomly selected exam will require more than 15 minutes to grade

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