The equation -3y=15-4x rewritten in slope intercept form is

Slove 5y-3w if y=2 and w=-3

Morgarella [4.7K]

Answer: 19

Step-by-step explanation:

Just plug in your variables

5(2) - 3(-3)

10 + 9

7 0

3 years ago

Read 2 more answers

Hi guys, I need help to solve this. I can’t understand how the percentage is calculated in (a) and (b) and how the rent is calcu

lana [24]

Answers :

(A) 18.33%
(B) 21.65%
(C) about 173.33
(D) i really have no way of finding the angles for you, you could try to find them yourself; or maybe just leave it blank?

<h3>OK, so judging from the bar shown : </h3>

It looks like Rent takes up 1/3 of the space so 33.33..%

It also looks like Loan Repayment + Savings is another 33.33..% but Savings is slightly larger than Loan Repayment so you could just estimate Savings to be 55% and LR to be 45% of the 1/3 space.

55% of 33.33.. = 18.33%

45% of 33.33.. = 14.99%

LR looks equal to Entertainment making it another 14.99.

It also looks like Entertainment + Electricity + Groceries = the last 33.33..%

And since we know Entertainment = 14.99 / 45% of 33.33..

Making Electricity and Water ABOUT 35% of 33.33... which is 11.66

And Groceries is somehow 20% of 33.33 = 6.66

Rent = 33.33..%
Savings = 18.33%
Loan Repayment 14.99%
Entertainment 14.99%
Electricity and Water 11.66%
Groceries = 6.66%

<h3>All of these added together equal ABOUT 100%</h3>

4 0

3 years ago

A normal population has a mean of 19 and a standard deviation of 5.

dangina [55]

Answer:

a) $Z = 1.2$

b) 38.49% of the population is between 19 and 25.

c) 34.46% of the population is less than 17.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. If we need to find the probability that the measure is larger than X, it is 1 subtracted by this pvalue.

For this problem, we have that

A normal population has a mean of 19 and a standard deviation of 5, so $\mu = 19, \sigma = 5$ .

(a) Compute the z value associated with 25

This is Z when $X = 25$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 19}{5}$

$Z = 1.2$

(b) What proportion of the population is between 19 and 25?

This is the pvalue of Z when $X = 25$ subtracted by the pvalue of Z when $X = 19$ .

X = 25 has $Z = 1.2$ , that has a pvalue of 0.8849.

X = 19 has $Z = 0$ , that has a pvalue of 0.5000.

So 0.8849-0.500 = 0.3849 = 38.49% of the population is between 19 and 25.

(c) What proportion of the population is less than 17?

This is the pvalue of Z when $X = 17$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19}{5}$

$Z = -0.40$

$Z = -0.40$ has a pvalue of 0.3446.

This means that 34.46% of the population is less than 17.

7 0

3 years ago

A gift box has the shape of a rectangular prism. How much wrapping paper do you need to cover the box?

Natasha_Volkova [10]

Answer:

768 in²

Step-by-step explanation:

Surface Area = 2(15*14) + 2(15*6) + 2(14*6)

Surface Area = 2(210 + 90 + 84)

Surface Area = 2(384)

Surface Area = 768

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

3 years ago

What is the meaning of a composite number?

zaharov [31]

Composite number is a positive integer that can be formed by multiplying together two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than 1 and itself.[1][2] Every positive integer is composite, prime, or the unit 1, so the composite numbers are exactly the numbers that are not prime and not a unit.

For example, the integer 14 is a composite number because it is the product of the two smaller integers 2 × 7. Likewise, the integers 2 and 3 are not composite numbers because each of them can only be divided by one and itself

7 0

4 years ago