Question

A corn silo contains 8,250 cubic feet of

Answer 1

Answer:

$V=1,080t$

Step-by-step explanation:

Remember that

$1\ h=60\ min$

so

$1\ min=(1/60)\ h$

we know that

The rate is $18\frac{ft^3}{min}$

Convert to ft³/h

$18\frac{ft^3}{min}=18\frac{1}{(1/60)}=18(60)=1,080\frac{ft^3}{h}$

The equation that can be used to find the Volume  V of the corn in the silo hours after loading begin represent a proportional relationship

$V=kt$

where

V is the volume of the corn in the silo

t is the time in hours

k is the constant of proportionality  or rate

we have

$k=1,080\frac{ft^3}{h}$

therefore

$V=1,080t$