When I get a job and so you will have money set aside for when the government comes and takes everything you own.
Income before tax is the income that is before it has been taxed or before applying deduction.
<u>Explanation:</u>
An individual or organization's salary before taxes and deductions is before tax income for that company, organisation or for a single individual.
For singular pay, it is determined as the person's wages or pay, venture and resource gratefulness, and the sum produced using some other wellspring of pay. In an organization, it is determined as incomes less costs.
Answer:
D. He will have a tough time finding a job that fits his interests.
Explanation:
The other answers require a sense of self-awareness.
Strong feeling its Capitalism.
Answer:
a-The present value of revenue in the first year is $61,085.92.
b-The total time it would take to pay for its price is 2.44 years of 29.33 months.
Explanation:
a-
Let the function of the revenue earned is given as
![S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fp%3E%3Cp%3EThe%20present%20value%20is%20given%20as%20%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5Ea_b%20%7BS%28t%29e%5E%7B-rt%7D%7D%20%5C%2C%20dt)
Here
- a and b are the limits of integral which are 0 and 1 respectively
- r is the rate of interest which is 5% or 0.05
- S(t) is the function of value which is
![S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fli%3E%3C%2Ful%3E%3Cp%3ESo%20the%20equation%20becomes%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5E0_1%20%7BS%28t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%2B38000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2838000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D8113.7805%2B18764.4669%2B34207.6751%5C%5CPV%3D61085.9225)
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as

The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:

So the total time it would take to pay for its price is 2.44 years of 29.33 months.