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Gennadij [26K]
3 years ago
11

Find the third fourth and fifth terms of the sequence defined by a1=1, a2=3, and a n =(-1)n a n-2 for n>3

Mathematics
1 answer:
Maslowich3 years ago
5 0

We have been given that

a_1=1\\  a_2=3\\
a_ n =(-1)^n a _{n-2} \text{ for } n>3

In order to find the third term, we substitute n=3

a_ 3 =(-1)^3a _{(3-2)}\\
\\
a_ 3 =(-1)^3 a _{1}

Substituting the given value of a_1

a_ 3 =(-1)^3 \times 1\\
\\
a_3=-1\times 1\\
\\
a_3=-1

Similarly, we can find the fourth term by plugging n=4

a_ 4 =(-1)^4a _{(4-2)}\\
\\
a_ 4 =(-1)^4 a _{2}\\
\\
a_4= 1\times 3\\
\\
a_4=3

Therefore, the third term is -1

And the fourth term is 3


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4 0
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How do you do this?<br> Please help
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substituting 45 - p for h in 2h + 0.333p = 30, we get:

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7 0
3 years ago
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