In circle A shown below, BD with a line above is the diameter and the measure of arc CB is 54 degrees. What is the measure of an
gle DBC
2 answers:
The complete question in the attached figure
we know that
the triangle ACB is an isosceles triangle
AC=AB----------> equals to the radius
so
∡ACB=∡CBA
the angle ∡CAB is equals to 54° by central angle
so
180°=54°+2*∡CBA--------> ∡CBA=[180-54]/2-----> 63°
∡CBA=63°
∡DBC=∡CBA-----------> ∡DBC=63°
the answer is
∡DBC=63°
we know that
the triangle ACB is an isosceles triangle
AC=AB----------> equals to the radius
so
∡ACB=∡CBA
the angle ∡CAB is equals to 54° by central angle
so
180°=54°+2*∡CBA--------> ∡CBA=[180-54]/2-----> 63°
∡CBA=63°
∡DBC=∡CBA-----------> ∡DBC=63°
the answer is
∡DBC=63°
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Answer:
x = 250°
Step-by-step explanation:
"Angle formed between a chord and tangent intersecting on a circle measure the half of the intercepted arc"
From the figure attached,
Angle between the chord and the tangent = 55°
Measure of intercepted arc (minor arc AB) = h°
Therefore, 55° =
And m(minor arc AB) + m(major arc AB) = 360°
h° + x° = 360°
110° + x° = 360°
x° = 360° - 110°°
x = 250°
Therefore, measure of the intercepted arc is 250°.
