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3 years ago

60000/23/35767755x100000 whats the answer?

1 answer:

6 0

This would be a great question to just plug into a calculator. I'm sure you will find the answer quite easily if you use a calculator.

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Evaluate 7^2 + (4x5) - 2^3

Phoenix [80]

So it would be 49+(20)+8

= 77

7 0

3 years ago

(6-7i)+(5+4i)= (simplified)

GarryVolchara [31]

Answer:

11-3i

Step-by-step explanation:

6-7i+5+4i=6+5-7i+4i=11-3i

8 0

3 years ago

Read 2 more answers

Which results only in a horizontal compression of y=1/x by a factor of 6

yan [13]

we are given

parent function as

$y=\frac{1}{x}$

Suppose, we are given a function y=f(x) is compressed horizontally by ''b'' units

where b>1

so, we can write as

new function as

$y=f(bx)$

Here, it is compressed by factor 6

so, we can replace x as 6x

and we get

$y=\frac{1}{6x}$

so, option-A.........Answer

7 0

3 years ago

Read 2 more answers

Which is the best approximation of the volume of a cone with the same base and height as the cylinder?

Sever21 [200]

If the volume of a cylinder is x, then the volume of a cone with same height and diameter is x/3

so

if the cone is 72ft³ then the cone with same base and height is 72/3ft³=24ft³

answer is A

3 0

3 years ago

2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.

Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by $h(t)= -16t^2+15t + 12$

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled $h(t)= -16t^2+15t + 12$ ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

$h'= -32t+15$

For critical point put h'=0,

$-32t+15=0$

$t=\frac{15}{32}$

$t=0.46875$

Derivate again w.r.t. t,

$h''= -32$

It is maximum at t=0.46875.

Substitute t in equation (1),

$h(0.46875)= -16(0.46875)^2+15(0.46875)+12$

$h(0.46875)= -3.515625+7.03125+12$

$h(0.46875)= 15.515625$

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

$-16t^2+15t + 12=0$

Apply quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=-16 , b=15, c=12

$t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}$

$t=\frac{-15\pm\sqrt{225+768}}{-32}$

$t=\frac{-15\pm\sqrt{993}}{-32}$

$t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}$

$t=−0.515,1.453$

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0

3 years ago