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RUDIKE [14]
3 years ago
6

What is the greatest number of planes determined by four collinear points

Mathematics
1 answer:
Sidana [21]3 years ago
5 0
The greatest number of planes determined by four collinear points is ∞ , infinity
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The sequence an = one third (3)n - 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average
charle [14.2K]

9514 1404 393

Answer:

  6

Step-by-step explanation:

The slope of the line between (3, 3) and (4, 9) is given by the slope formula:

  m = <average rate of change> = (y2 -y1)/(x2 -x1)

  m = (9 -3)/(4 -3) = 6/1

  m = 6

The average rate of change on the interval [3, 4] is 6.

7 0
2 years ago
Read 2 more answers
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
2 years ago
The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th
Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

dC = Cv.dv + Ct.dt

Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44

Relative Error

dC / C @(T = 8, v=23)  * 100 = 19 %

8 0
2 years ago
How do i find the ratio 2:9
Ganezh [65]
The ratio of 2:9 has to be 2:9 do to the fact you can't simplify the fraction 2/9.
Hoped I helped.
6 0
3 years ago
Complete the table and determine whether the data is proportional and explain why
Valentin [98]

Answer:

in distance it goes 3,6,9,12,15

Step-by-step explanation:

thats all i know i hope my answer anwsers nyour questionand have a great time and get a lot of A+ ✍✍

7 0
3 years ago
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