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VikaD [51]
3 years ago
8

What is the perimeter of the polygon? Assume all angles are right angles.

Mathematics
1 answer:
malfutka [58]3 years ago
7 0
Perimeter of given
square=18*4=72
You might be interested in
What’s the answer???????
Hunter-Best [27]

Answer:

2 1/2

Step-by-step explanation:

1st, convert the fractions

2 2/3 = 2 4/6 = 16/6

5 1/6 = 31/6

31/6-16/6 = 15/6 = 2 3/6 = 2 1/2

6 0
4 years ago
Solve the expression for a=12 , b=6 and c=3
enot [183]

Answer: 24

Step-by-step explanation: First, you fill in the values for each letter; replace any a with 12, replace any b with 6, and replace any c with 3. Then, enter the equation into the calculator like so, and it should be equal to 24.

I hope this helps. Have a nice day.

7 0
3 years ago
At Southside Middle school, 30% if the students play an instrument. There are 310 students. How many students play an instrument
Svetach [21]
30% converted to a decimal is 0.30
310 x 0.3 = 93 students play an instrument
3 0
3 years ago
Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?
Marta_Voda [28]

Perimeter=19.9units

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle,  and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units

From A to C:

d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units

From B to C:

d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units

Now, calculating the perimeter, we have:

Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units

Have a nice day!

5 0
3 years ago
Solve for x: 2 over quantity x plus 2 plus 1 over 5 equals 6 over quantity x plus 5. x = 0 x = −13 x = 13 x = 0 and x = 13
grandymaker [24]

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

\frac{2}{x+2}+\frac{1}{5}=\frac{6}{x+5}

2. You need to sum the fractions located on the left member, as following:

\frac{10+(x+2)}{5(x+2)}=\frac{6}{x+5}

x=(12+x)(x+5)=6(5x+10)

3. Simplify it and you will obtain a quadratic equation. Solve it by factor out x:

x^{2} -13x=0\\ x(x-13)=0\\ x=0; x=13

Therefore, the answer is: x=0; x=13

4 0
4 years ago
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