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jasenka [17]
3 years ago
14

A girls height is 3 1/3 feet .a giraffes heights is 3 times than the girl.how many inches than the girl ?

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

Girl's height: 3 1/3  ft

Giraffes height: 10 ft

Difference between the heights: 6  2/3

Step-by-step explanation:

Ok, so the question is  bit vague, so I'm not sure which of the following answers your are looking for, that's for you to put.

We have the girl's height.

We multiply the girl's height by 2 to get the giraffe's height.

We subtract the girls height from the giraffe's height to get the difference.

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(x^2y+e^x)dx-x^2dy=0
klio [65]

It looks like the differential equation is

\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0

Check for exactness:

\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x

As is, the DE is not exact, so let's try to find an integrating factor <em>µ(x, y)</em> such that

\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0

*is* exact. If this modified DE is exact, then

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}

We have

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu

Notice that if we let <em>µ(x, y)</em> = <em>µ(x)</em> be independent of <em>y</em>, then <em>∂µ/∂y</em> = 0 and we can solve for <em>µ</em> :

x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}

The modified DE,

\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0

is now exact:

\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}

So we look for a solution of the form <em>F(x, y)</em> = <em>C</em>. This solution is such that

\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}

Integrate both sides of the first condition with respect to <em>x</em> :

F(x,y) = -e^{-x}y - \dfrac1x + g(y)

Differentiate both sides of this with respect to <em>y</em> :

\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C

Then the general solution to the DE is

F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}

5 0
3 years ago
For the school play 40 rows of chairs are set up there are 22 chairs in each row how many chairs are there
liq [111]
If you had one row, you would have 22 chairs.

If you had two rows, you would have 22+22=44 chairs.

If you had three rows, you would have 22+22+22 chairs, or 66 chairs.

See the pattern?

If you had 40 rows, you would add 22 40 times, or 22*40=880 chairs.

Hope this helps!
6 0
3 years ago
Read 2 more answers
Subject:Mathematics ​
djverab [1.8K]

Answer:

I'm also struggling with that too

7 0
3 years ago
Read 2 more answers
Find the value of x:
nadya68 [22]

Answer:

x = 3

Step-by-step explanation:

These angles are vertical angles. Vertical angles equals to on another but on the opposite side. Since they equal to another you do:

(10x + 1) = (12x - 5)

Add 5 on both sides:

10x + 6 = 12x

Subtract 10x on both sides:

6 = 2x

Divide 2 on both sides:

3 = x

6 0
3 years ago
Read 2 more answers
In a recent snail race, a snail traveled a distance of 1 1/6 inches in 2 minutes. Find the number if inches traveled per minute
Alecsey [184]

Answer:

For inch/min =0.9167 inch/min

For min/inch = 1.0908 min/inch

Step-by-step explanation:

The snail in the race traveled 11/6 inches in 2 minutes.

The number of inches per minute is equal to = (11/6)/(2)

= 11/12

=0.9167 inch/min

The number of minutes per inch is equal to = 1/(inch per min)

= 1/0.9167

= 1.0908 min/inch

Minutes per inch is gotten by taking the inverse of inch/min or dividing the number of minutes by number of inches

6 0
3 years ago
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