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Harrizon [31]
3 years ago
6

WILL CROWN BRAINLIEST, 5/5 RATING, AND LIKE!

Mathematics
2 answers:
Genrish500 [490]3 years ago
4 0

Hey there!

If we have two white marbles and seven purple marbles, our first probability is out of nine.

First of all, we have the probability of selecting a purple marble, 7/9.

Now, if we do not replace it, there are only eight marbles left. Therefore, getting a white marble is 2/8, or 1/4.

We multiply these probabilities together to get our answer to a.

7/9(1/4)= 7/36

a. 7/36

Now, let's do b. We have 2/9, and then 1/8, giving us 1/36.

b. 1/36

Now, let's calculate selecting two purple to help us with C.

We have 7/9, and then 6/8, or 3/4.

7/9(3/4)= 7/12

Since there is a majority of purple marbles, there is a C) greater probability of selecting two purple marbles in a row.

I hope this helps!

Rzqust [24]3 years ago
4 0

Answer:

A. 7:9 B. 1:4 C. Purple

Step-by-step explanation:

A. Because there are 7:9 B. Because 1:4 C. Because Purple has more

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GO.o has 3 orange picks for every 2 green. If there are 25 picks in all, how many picks are orange?
Reika [66]

Given

GO.o has  3 orange picks for every 2 green

there are 25 picks in all

Find out how many picks are orange.

To proof

As given in question

GO.o has  3 orange picks for every 2 green

i.e the ratio of orange to every green becomes

\frac{Orange}{Green}:\frac{3}{2}

total number of picks = 25

let the GO.o pick of  3 orange picks for every 2 green =x

than the equation becomes

3x + 2x = 25

5x = 25

x = 5

Than

the number of oranges = 3x

putting the value  of x

                                     = 15

the number of green = 2x

                                  =  10

thus the 15 picks are orange.

Hence proved

4 0
3 years ago
Read 2 more answers
Find the two small as possible solutions ​
solong [7]

Answer:  \bold{b)\quad \dfrac{5}{6},\ \dfrac{25}{6}}

<u>Step-by-step explanation:</u>

12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)

\text{Use the Unit Circle to determine when}\ cos=\dfrac{1}{2}\quad \rightarrow \quad\text{at}\ \dfrac{\pi}{3}\ and \ \dfrac{5\pi}{3}\\\\\\\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\qquad and\qquad \dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\\\\\\\bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\quad and\quad \bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\\\\\\.\qquad \qquad \large\boxed{x=\dfrac{5}{6}\qquad and \qquad x=\dfrac{25}{6}}

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3 years ago
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In the data set below what is the lower quartile 16,26, 48,56,61,85,88,88,88,91,91​
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Answer:

48

Step-by-step explanation:

First find the median:

16,26,48,56,61,85,88,88,88,91,91​

85 is the median.

Now, find the median of the first set of bold numbers.

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The median of the first bold set of numbers will be lower quartile.

The lower quartile is 48.

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