《ANSWER》
《LINEAR EQUATIONS》
Solving all we get as
↪1) 5 (x -2) = 5x - 7
since after solving X is cancelled , NO SOLUTION
↪2) -3 (x - 4) = -3x + 12
SINCE after solving X is any value , infinitely many solutions
↪3) 4 (x + 1) = 3x + 4
solving we get as , 4x+ 4 = 3x + 4 =》 X =0
only one solution
↪4) -2 (x-3) = 2x - 6
Only one solution
↪5) 6 (x + 5) = 6x + 11
NO SOLUTION
All the equations are solved by the distributive law of algebra
To get the volume, you need the area of the sides of the square.
The total surface area is 96, with 6 sides. To get the surface area of just one side, divide 96 by 6, which gets you 16. The surface area of a single square is 16. To get one side of the square, divide that by 4 because there are 4 sides.
Now, multiply 16 by 4 to get the volume.
The volume is 64 cubed milllimeters.
brainlieest?
Also i hope this helped
Step-by-step explanation:
2x = y-10
Rewrite as: 2x + 10 = y
Therefore:
2x+10 = y
2x +7 = 2y
Subtract the equations:
2x + 10 = y
- 2x + 7 = 2y
______________
3 = -y
Therefore y = -3
Substiture y = -3 into the second equation:
2x + 7 = 2(-3)
2x + 7 = -6
2x = -13
x= -6.5
Answer : (-6.5, -3)
Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.
Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.