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Pani-rosa [81]
3 years ago
6

To increase and decrease an amount by 7%, what single multiplier would you use?

Mathematics
2 answers:
Mila [183]3 years ago
6 0

We will solve the problem for both cases:


Case 1:

If the amount increases by 7% we have the number for which we are going to multiply is given by:

x = (\frac{1}{100}) * (100 + 7)

x = (\frac{1}{100}) * (107)\\x = 1.07


Case 2:

If the amount decreases by 7% we have the number for which we are going to multiply is given by:

x = (\frac{1}{100}) * (100-7)

x = (\frac{1}{100}) * (93)\\x = 0.93


Answer:

single multiplier you would use for each case is:

x = 1.07 (increase)

x = 0.93 (decrease)

UNO [17]3 years ago
3 0
To increase an amount by 7%, you would want to use 1.07 as the multiplier. To decrease it, you would use 0.93 
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3 years ago
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Aleks04 [339]

To get the volume, you need the area of the sides of the square.

The total surface area is 96, with 6 sides. To get the surface area of just one side, divide 96 by 6, which gets you 16. The surface area of a single square is 16. To get one side of the square, divide that by 4 because there are 4 sides.

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neonofarm [45]

Step-by-step explanation:

2x = y-10

Rewrite as: 2x + 10 = y

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hammer [34]

Answer:  The answer is (B) ∠SYD.


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We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

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The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.

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