Hi there!
24. 6x² + 19x + 3
1 3 multiply 6 × 3 = 18
6 1 multiply 1 × 1 = 1
18 + 1 = 19
(x + 3)(6x + 1)
I just simply found the two factors of 6 and 3 that can add up to 19.
This way is useful when the a and c don't have much factors.
27. 5y² + 13y + 6
1 2 5 × 2 = 10
5 3 1 × 3 = 3
10 + 3 = 13
(x + 2)(5x + 3)
30. 16x² + 16x + 3
For this one, 16 has a lot of factors. So you can try "Grouping" method.
You multiply 16 and 3. 16 × 3 =48
Find the factors of 48 that can add up to 16.
Hmm.. 12 and 4 would be great.
Then rewrite the equation.
16x² + 12x + 4x + 3
We would factor 16x² + 12x and 4x + 3 separately.
16x² + 12x 4x + 3 can't be factored more.
4x(4x + 3) 1(4x + 3)
(4x + 1)(4x + 3)
So your answers are....
24. (x + 3)(6x + 1)
27. (x + 2)(5x + 3)
30. (4x + 1)(4x + 3)
Hope this helped!!
Answer:
50 pages per hour
Step-by-step explanation:
6x-5=4x+5
+5
6x=4x + 0
-4x
2x=0
x =0
probably to late but whatever
Hello!
1/2 = 0.5 as a decimal
0.5 ÷ 2 = 0.25
That means you walk 1 mile in 0.25 of an hour. Multiply this by three:
0.25 × 3 = 0.75
Answer:
It will take you 0.75 (or 3/4) hour to walk 3 miles.
Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
