Answer:
y = 84
Step-by-step explanation:
1) add 3 to both sides of your equation to cancel out the -3
end up with: (1/3)y + 14 = (1/2)y
2) multiply both sides of your equation by 2 to cancel out the (1/2)
end up with: (2/3)y + 28 = y
3) subtract (2/3)y from both sides of the equation to cancel out the positive (2/3)y
end up with: 28 = (1/3)y
4) multiply both sides of the equation by 3 to cancel out the (1/3)
end up with: 84 = y
Answer:
.
Step-by-step explanation:
Using first order linear differential equation:


finding integrating factor:
I.F = 
I.F =
now,



hence the solution is

The strategy is following
Smaller number subtract from the greater. Result is distance between two numbers
For example you have 3 and 8
8-3-5
5 is the distance between 3 and 8
It also works with the negative numbers, for example 3 and -5
3-(-5)=8
Answer:
-30bc + 50bd
Step-by-step explanation:
3a + 5b/3c - 5d = 3a - 5b/3c - 5d
(3c - 5d)(3a - 5b) = (3a + 5b)(3c - 5d)
9ca - 15bc - 15da + 25db = 9ac - 15ad + 15bc - 25bd
9ca -15bc - 15da + 25db - 9ac + 15ad - 15bc + 25bd
9ca and -9ac and -15da and 15ad cancel each other out, so
-30bc + 50db is left
Answer:
3(u^2 +u-3)
-------------------
u(u-3)^2
Step-by-step explanation:
u 1
---- + -------
u-3 u
-------------------------
u-3
----------
3
Get a common denominator for the numerator
u *u 1(u-3)
---- + -------
(u-3)u u(u-3)
-------------------------
u-3
----------
3
u *u + (u-3)
-----------
(u-3)u
-------------------------
u-3
----------
3
Now use copy dot flip
u *u + (u-3) 3
----------------- * -------------
(u-3)u u-3
3(u^2 +u-3)
-------------------
u(u-3)^2