Ask question

Ask question

All categories

3 years ago

10

A group of 6 friends want to share 8 pears evenly. All of the pears are the same size. How many pears should each friend receive

? Explain how the friends should cut the pears and divide them.

2 answers:

Leviafan [203]3 years ago

6 0

Everyone should get 1 2/5 of a pear. They should give everyone one whole pear then cut the left over 2 into 5 sections and give everyone two sections

konstantin123 [22]3 years ago

4 0

1.3333333 pears each

You might be interested in

The surface area of this regular pyramid is 1040 cm2. The base is a regular pentagon with side b = 16 cm and slant height l =15

Valentin [98]

Answer:

(a) = 11 cm

Step-by-step explanation:

The formula for finding the surface area of a regular pyramid is B + (1/2*P*l), with B being the area of the base, p being the perimeter of the base, and l being the slant of the pyramid.

The area of a pentagon can be solved using the formula 1/2*a*p, with a being the apothem and p being the perimeter of the pentagon.

B + (1/2*80*15) = 1040
B + 600 = 1040
1040 - 600 = 440 (440 is the area of pentagon)
1/2*a*(16*5) = 440
40*a = 440
440/40 = 11

The apothem is 11 cm. Hope this helps!

6 0

3 years ago

Let f(x)=2.912345x^2+3.131579x-0.099999

Rudiy27

A.) Integers are positive and negative counting numbers. So, in order to find the integer coefficients, round off the coefficients in the equation to the nearest whole number. The function for g(x) is:

g(x) = 3x²+3x

B.) Substitute x=4 to the two functions.

f(x) = 2.912345x²<span>+3.131579x-0.099999
</span>f(4) = 2.912345(4)²+3.131579(4)-0.099999
f(4) = 59.023837

g(x) = 3x²+3x
g(4) = 3(4)²+3(4)
g(4) = 60

C.) The percentage error is equal to:

Percentage error = |g(4) - f(4)|/f(4) * 100
Percentage error = |60 - 59.023837|/59.023837 * 100
Percentage error = 1.65%

D.) If x is a large number, for example x=10 or x=20, then g(x) would be an overestimate. This is because the value of x is raised to the power of 2. So, as the x increases, the corresponding function would increase exponentially. Even at x=4, g(x) is already an overestimate. What more for larger values of x? That means that the gap from the true answer f(x) would increase.

5 0

3 years ago

How do you get the equation of the line in fully simplified slope-intercept form?

Igoryamba

Answer:

y= -2/5 x -4

Step-by-step explanation:

So the equation is y=mx+b. Where m=slope and b=y-intercept. To find b, you would see at what point does the line cross the y axis. That would be at -4 so, -4 would be the b or y-intercept. To find m, you would take two points on the line and use this equation:

m=(y2 - y1 )/(x2 - x1)

If you were using the points, (-10,0) and (0, -4) the equation would be:

m=(-4-0) / (0+10)

So, m= -2/5

The equation of the line would end up being:

y= -2/5 x -4

4 0

3 years ago

What is the sum of these expressions: (-3.5t - 4s + 4.5) + (-7.1 - 0.3s + 4.1t)

dmitriy555 [2]

-4.3s + 0.6t - 2.6 is the answer

4 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago