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3 years ago

An object has a mass of 744 g and a volume of 186cm^3. What is the density of the object

1 answer:

5 0

Density =Mass/volume

Define variables:
Volume is 186cm^3
Mass is 744g
Density is ?

Place into formula:
So,
Density=744g/186cm^3 = 4g/cm^3

Answer:
The density is 4g/cm^3.

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Find the equation of a line that passes through (0,0) that is perpendicular to 2x+3y=-6

Dovator [93]

The slope-intercept form of a line:

$y=mx+b$

m - slope

b - y-intercept

Convert 2x + 3y = -6 to the slope-intercet form:

$2x+3y=-6$ subtract 2x from both sides

$3y=-2x-6$ divide both sides by 3

$y=-\dfrac{2}{3}x-2$

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $m_1=-\dfrac{2}{3}$

Therefore

$m_2=-\dfrac{1}{-\frac{2}{3}}=\dfrac{3}{2}$

We have the equation of a line:

$y=\dfrac{3}{2}x+b$

Put the coordinates of the point (0, 0) to the equation:

$0=\dfrac{3}{2}(0)+b$

$0=b\to b=0$

Answer: $\boxed{y=\dfrac{3}{2}x}$

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3 years ago

the distance between california and mexico border is 100 miles less than thrice the distance between california and washington.

harina [27]

Answer: B. 3m-100

Step-by-step explanation:

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2 years ago

F(x) = 1?-1.9(x) = x - 2. Find (a) ( + g)(3)

ValentinkaMS [17]

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Step-by-step explanation:

Big brain time.

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4 years ago

you have $20 to spend at the snack bar all the snacks at the snack bar cost $1.25 how much money will you have left if you buy 1

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You will have $5 left because if you spend 1.25 on 12 snacks you will spend $15

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3 years ago

Read 2 more answers

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago