Answer:
1 pear = $0.75; 1 orange = $0.65
Step-by-step explanation:
(1) 3P + 4O = 4.85
(2) 3P + 10O = 8.75 Eqn (2) - Eqn (1)
3P + 10O – 3P – 4O = 8.75 – 4.85 Combine like terms
6O = 3.90 Divide each side by 6
O = $0.65 Substitute into Eqn (1)
3P + 4×0.65 = 4.85
3P + 2.60 = 4.85 Subtract 2.60 from each side
3P = 2.25 Divide each side by 3
P = $0.75
Oranges cost $0.65 each and pears are $0.75 each
Answer:
After 6 months, the interest generated by the investment would be $21.10.
Step-by-step explanation:
To determine the interest that Preston McCord could earn by investing $ 1,400 in an account that pays 3.2% annual interest compounded monthly, leaving said money invested for a period of 6 months, it is necessary to perform the following calculation:
X = 1,400 x (1 + 0.032 / 6) ^ 0.5x6
X = 1,421.10
1421.10 - 1400 = 21.10
Thus, after 6 months, the interest generated by the account will be $ 21.10.
Answer:
no question pls give and I can think
4x+2x^2+3x-2x+7
First, you would combine like terms. In this case, you would add 4x and 3x then subtract 2x.
2x^2+5x+7
5x^2-2x+3+4x-2x^2
Once again, you must combine like terms. Subtract 2x^2 from 5x^2, then subtract 2x from 4x.
3x^2+2x+3
There you go! Hope it helps
-Lacy
