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3 years ago

Pls help me out!! lol

Mathematics

1 answer:

miskamm [114]3 years ago

8 0

Answer:

the answer is D

Step-by-step explanation:

it is D because in normal y=mx+b form the given equasion is y= -1/2x + 3/2. for a line to be parallel to another line, they both must have the same slope, D is the only answer with the same slope as the slope from the given equasion

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(15 points) + (brainliest)

LiRa [457]

Im pretty sure it would be product

7 0

4 years ago

If RSTU is a rhombus, find the measure of angle RUT.

Schach [20]

Finding x:

We know that the diagonals of a rhombus bisect its angles

So, since US is a diagonal of the given rhombus:

∠RUS = ∠TUS

10x - 23 = 3x + 19 [replacing the given values of the angles]

7x - 23 = 19 [subtracting 3x from both sides]

7x = 42 [adding 23 on both sides]

x = 6 [dividing both sides by 7]

Finding ∠RUT:

We can see that:

∠RUT = ∠RUS + ∠TUS

Since we are given the values of ∠RUS and ∠TUS:

∠RUT = (10x - 23) + (3x + 19)

∠RUT = 13x - 4

We know that x = 6:

∠RUT = 13(6)- 4

∠RUT = 74°

8 0

3 years ago

Kit bought a soft drink and a sandwich for $9.00. What was the price of each of the sandwich cost 3.5 times as much as the drink

Rainbow [258]

Sandwich cost $7.70 and the soda costs $2.20.

8 0

3 years ago

A certain backpack costs $22, and there is 4% sales tax. What is one way to determine what the amount of sales tax will be? Sele

Mademuasel [1]

Answer:

$0.88

Step-by-step explanation:

cost per 1% = 22 ÷ 100 = 0.22

⇒ cost of 4% = 4 x 0.22 = 0.88

4% = 4/100 = 0.04

⇒ 4% of 22 = 0.04 x 22 = 0.88

Step-by-step explanation:

8 0

3 years ago

. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i

KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a) which resulted in the wrong answer.

So, the polynomial would be:

$(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0$

7 0

3 years ago