See the attached picture with letters to better understand the problem
Part 8)
we know that
The angle bisectors of a triangle intersect in a point (
incenter) that is equidistant from the three sides of the triangle
so
OF=OD=OE-----> <span>are the radii of the inscribed circle
</span>
the triangle ODB and the triangle OBE are congruent
so
applying the Pythagoras Theorem
OB²=OD²+DB²------> solve for OD
OD²=OB²-DB²------> (√28)²-5²-----> OD²=28-25-----> OD=√3 units
radius is equal to OD
therefore
the answer part 8) isradius is √3 unitsPart 9) What is the value of x?
we know that
in the quadrilateral FOEC <span>the sum of the internal angles must be equal to 360 degrees
</span>so
360=90+90+60+x
x=360-240
x=120°
the answer Part 8) isx=120°