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nasty-shy [4]
3 years ago
12

Why is it possible to have right equilateral triangles

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
Not possible because it has to be equal and if it had a right angle it wouldnt be equal
Paraphin [41]3 years ago
4 0
No it is not possible
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What is the value of x and the length of segment DE?
Mandarinka [93]

Answer:

Part 1) x=6.6\ units

Part 2) DE=16.2\ units

Step-by-step explanation:

Part 1) Find the value of x

we know that

Triangles CDF and FDE are similar

therefore

The ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

CD/FD=FD/DE

\frac{5}{9}=\frac{9}{2x+3} \\ \\5*(2x+3)=9*9\\ \\10x+15=81\\ \\10x= 81-15\\ \\10x=66\\ \\ x=6.6\ units

Part 2) Find the length of DE

DE=2x+3

substitute the value of x

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3 years ago
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Step-by-step explanation:

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3 0
3 years ago
4(2x+8)=10x+2-2x+30 what is x?
Anastaziya [24]

Let's solve your equation step-by-step.

4(2x+8)=10x+2−2x+30

Step 1: Simplify both sides of the equation.

4(2x+8)=10x+2−2x+30

(4)(2x)+(4)(8)=10x+2+−2x+30(Distribute)

8x+32=10x+2+−2x+30

8x+32=(10x+−2x)+(2+30)(Combine Like Terms)

8x+32=8x+32

8x+32=8x+32

Step 2: Subtract 8x from both sides.

8x+32−8x=8x+32−8x

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Step 3: Subtract 32 from both sides.

32−32=32−32

0=0

Answer:

All real numbers are solutions.

5 0
3 years ago
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aleksley [76]
The answer is x=1
x^5=1
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