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nasty-shy [4]
3 years ago
12

Why is it possible to have right equilateral triangles

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
Not possible because it has to be equal and if it had a right angle it wouldnt be equal
Paraphin [41]3 years ago
4 0
No it is not possible
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2 years ago
NEED Math help please?
Tamiku [17]

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Step-by-step explanation:5,7 3,9

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3 years ago
I have no idea. Please I need just answers. Thank you. ​
igomit [66]

Answer:

Step-by-step explanation:

1km = 1000m

5a. 5.768km = 5768m = 57.7m

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Rule is applied for all the other questions too.

3 0
3 years ago
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
3 years ago
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