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Genrish500 [490]
4 years ago
11

What is the range of the data?

Mathematics
2 answers:
Lelu [443]4 years ago
8 0
The range would be the difference between the maximum number and the minimum number so that would be:
64 - 45 = 19

So 19 is your answer.
MatroZZZ [7]4 years ago
5 0

Answer:

19

Step-by-step explanation:

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Simplifique a expressão 10ny-10x+10ny+10y
IRISSAK [1]

Responder:

10 (2ny- (x-y))

Explicación paso a paso:

Dada la expresión 10ny-10x + 10ny + 10y, para simplificar la expresión, se deben seguir los siguientes pasos;

Paso 1; Separa la expresión en términos similares

= 10ny-10x + 10ny + 10y

= (10ny + 10ny) - (10x + 10y)

Paso 2: Factoriza los valores comunes en ambos paréntesis

10ny (1 + 1) - 10 (x-y)

= 10ny (2) - 10 (x-y)

= 20ny - 10 (x-y)

Factoriza nuestro valor común en ambos términos:

= 10 (2ny- (x-y))

3 0
4 years ago
Easy question someone please helppp
Leya [2.2K]

Answer:

Just ude math papa calculator

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the quadratic function f(x)=x^2+6x-2 In vertex form?
Yuliya22 [10]

Answer: Option D

f(x)=(x+3)^2 -k

Step-by-step explanation:

For a quadratic function of the form

ax ^ 2 + bx + c

The x coordinate of the vertice is:

x =-\frac{b}{2a}

In this case the function is:

f(x)=x^2+6x-2\\\\

So

a=1\\b=6\\c=-2

The x coordinate of the vertice is:

x=-\frac{6}{2*1}\\\\x=-3

The y coordinate of the vertice is:

f(-3) = (-3)^2 +6(-3) -2\\\\f(-3)=-11

The vertice is: (-3, -11)

The form e vertice for a quadratic equation is:

f(x)=(x-h)^2 +k

Where

the x coordinate of the vertice is h and the y coordinate of the vertice is k.

Then h=-3 and k =-11

Finally the equation f(x)=x^2+6x-2\\\\ in vertex form is:

f(x)=(x+3)^2 -k

6 0
3 years ago
Read 2 more answers
Need to know how to write 327.79 on a check in words
motikmotik
Three hundred and twenty seven point seven nine
3 0
3 years ago
Given: △PST, m∠S=90°, M∈PT,
swat32

Answer:

m∠P = 70°, m∠T = 20°, m∠SKP = 40° , and m∠MKT = 70°

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ PST

∵ m∠S = 90°

∴ m∠T + m∠P = 90° ⇒ interior angles of a triangle

∵ m∠SPK/m∠KPT = 5/2

- The ratio between the two angles are 5 : 2 , multiply the parts of the

  ratio by x, where x is a real number

∴ m∠SPK = 5x

∴ m∠KPT = 2x

∵ m∠SPK + m∠KPT = m∠P

∴ m∠P = 5x + 2x = 7x

- In ΔPKT

∵ KM ⊥ PT

∵ MP = Mt

∴ KM is perpendicular bisector of PT

∴ ΔPKT is an isosceles triangle with KP = KT

∵ KP = KT

∴ m∠KPT = m∠T

∵ m∠KPT = 2x

∴ m∠T = 2x

∵ m∠T + m∠P = 90°

∵ m∠P = 7x

∵ m∠T = 2x

∴ 2x + 7x = 90 ⇒ solve for x

∴ 9x = 90 ⇒ divide both sides by 9

∴ x = 10

∵ m∠P = 7x

∴ m∠P = 7(10) = 70°

∴ m∠P = 70°

∵ m∠T = 2x

∴ m∠T = 2(10) = 20°

∴ m∠T = 20°

- In ΔSKP

∵ m∠S = 90°

∵ m∠SPK = 5x = 5(10) = 50°

∴ m∠SKP = 180° - (90° + 50°) = 180° - 140° = 40° ⇒ interior angles of a Δ

∴ m∠SKP = 40°

- In Δ KMT

∵ m∠KMT = 90°

∵ m∠T = 20°

∴ m∠MKT = 180° - (90° + 20°) = 180° - 110° = 70° ⇒ interior angles of a Δ

∴ m∠MKT = 70°

3 0
3 years ago
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