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3 years ago

R=2s-6t+5 / 2 , solve for s

1 answer:

5 0

S = R + 3t - 5/2

multiply the r by the 2 and transfer -6t and 5 over to the left side which makes them +6t and -5, then divide the whole left side by 2 which gives you s

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7th grade math im really bad at math pls help

Soloha48 [4]

Answer:

Step-by-step explanation:

5x + x+96 = 180

6x+96 = 180

6x=84

x= 14

5 0

3 years ago

You are creating a decorated rope that is at least 20 feet long to create a rope you are using beads that are 6 inches long writ

Nitella [24]

Answer:

The number of beads used must be at least 40 to make a decorated rope of at least 20 feet length. The inequality is:

$6n\geq 240\\n\geq 40$

Step-by-step explanation:

Let the number of beads used be 'n'.

Now, length of 1 bead = 6 in

∴ Length of 'n' beads = $6\times n=6n\ in$

Now, minimum length of rope is 20 ft. Converting feet to inches, we get:

$20\ ft =20\times 12=240\ in$

Now, beads are inserted in the rope. So, the length of rope is same as the length of all the beads joined together.

As per question, length must be at least 20 ft or 240 in.

Therefore, the length of all beads joined together must be at least 240 inches. This gives,

$6n\geq 240\\n\geq \frac{240}{6}\\n\geq 40$

Therefore, the number of beads used must be at least 40 to make a decorated rope of at least 20 feet length.

5 0

4 years ago

Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

Absolute maximum is a point where the function has its greatest possible value.

Absolute minimum is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0

3 years ago

Jane wants to estimate the proportion of students on her campus who eat cauliflower. after surveying 39 students, she finds 4 w

stellarik [79]

Let $x$ be the number of students who eat cauliflower.

Therefore, $x=4$ .

Let $n$ be the total number of students surveyed.

Therefore, $n=39$

Thus, $\hat p$ $=\frac{4}{39} =0.10256$

Now, for 90% confidence level, from the table we know that $Z=1.645$ .

The formula for the interval range of proportion of students is :

$p= \hat p\pm Z\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Plugging in the values we get:

$p=0.10256\pm 1.645\sqrt{\frac{0.10256(1-0.10256)}{39}}=0.10256\pm 0.04858=0.15114, 0.05398$

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).

7 0

4 years ago

Help pleaseeee due at 4:00

Archy [21]

Answer:

the total cost would be $15,900

Step-by-step explanation:

hope this helped & good luck <33

5 0

3 years ago