Answer/Step-by-step explanation:
1. An isosceles ∆ has two equal sides. The base angles of an isosceles ∆ are also equal.
Therefore:
m<U = 54° (base angle of isosceles ∆)
m<T = 180 - (54 + 54) (sum of ∆)
m<T = 72°
2. ∆LMN is an isosceles ∆, therefore:
m<M = ½*(180 - 28) = 76°
m<N = m<M (base angle of isosceles)
m<N = 76°
3. ∆FEG is an isosceles ∆, because it has two equal base angles.
Therefore:
EF = FG
EF = 18 in
m<F = 180 - (23 + 23) = 134°
4. ∆PQR is an equilateral ∆. All sides and angles of an equilateral ∆ are equal.
Therefore:
m<P = 60°
m<Q = 60°
m<R = 60°
5. 4x + 23 = 10x - 1 (2 asides of an isosceles ∆ are equal)
Collect like terms
4x - 10x = -23 - 1
-6x = -24
Divide both sides by -6
x = 4
6. 2*(9x - 25) = 180 - 104 (base angles of isosceles ∆)
18x - 50 = 76
Add 50 to both sides
18x = 76 + 50
18x = 126
Divide both sides by 18
x = 7
7. 5x - 7 = 8x - 55 (base angles of an isosceles)
Collect like terms
5x - 8x = 7 - 55
-3x = -48
Divide both sides by -3
x = 16
8. 4x + 8 = 60° (angle of an equilateral ∆)
Subtract 8 from each side
4x = 60 - 8
4x = 52
Divide both sides by 4
x = 13
Answer:
D
Step-by-step explanation:
46 is your correct answer bc 30 plus 16 is 46
Answer:
Speed before applying brakes = 64.8
Step-by-step explanation:
The formula is given as:
Where
s is speed of car, and
d is length of skid marks
It is given that d = 175 ft, so we substitute and find the speed of the car before the brakes were applied.
Rounding to nearest tenth, that is 64.8
Having a fraction as a factor in a multiplication is operated by multiplying the numerator by any whole number and leaving alone the denominator, or if you multiply fractions, then you multiply numerators and denominators separately.
So in this case you have 8 halved apples, that is, 8 times one half apples:
8*(1/2)
this we solve by multiplying the whole number 8 times the numerator 1, and dividing by the denominator:
= 8*1/2
= 8/2
so you have 8 halved apples, which means
= 4
4 apples