10 members on the chess team have to play twice against everyone one the team how many games will need to o be played
1 answer:
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Answer:
5.1 days
Step-by-step explanation:
Given in the question,
initial amount of substance = 34 grams
k-value = 0.137
To find the half life of this substance we will use following formula
here N(0) is initial amount of substance
t is time in days
Plug values in the formula
1/2 = e^{-0.137t}
Take logarithm on both sides
ln(1/2) = ln( e^{-0.137t})
ln(1/2) = -0.137t
t = ln(1/2) / -0.137
t = 5.059
t ≈ 5.1 days (nearest to tenths)
Answer:
Step-by-step explanation:
Isolate the variable of y from one side of the equation.
-14=5(3y-10)-5y
<u>First, switch sides.</u>
Use the distributive property.
<u>DISTRIBUTIVE PROPERTY:</u>
A(B-C)=AB-AC
5(3y-10)
Multiply by expand.
5*3y=15y
5*10=50
15y-50-5y
15y-5=10y
= 10y-50
10y-50=-15
Add by 50 from both sides.
10y-50+50=-15+50
Solve.
10y=35
Then, you divide by 10 from both sides.
10y/10=35/10
Solve.
Divide the numbers from left to right.
35/10=7/2
y=7/2
Divide is another option.
7/2=3.5
- <u>Therefore, the correct answer is y=7/2.</u>
I hope this helps. Let me know if you have any questions.