2 years ago

A=1/2 bh for b i need help

1 answer:

5 0

You said that  A = 1/2 b h

Multiply each side by 2 : 2A = b h

Divide each side by 'h' : 2A/h = b

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A cube with sides 5 inches, and a pyramid with base edges 5 inches. What is the height, so that the volume of the cube and the p

Ostrovityanka [42]

15 inches is the height of the pyramid

Step-by-step explanation:

The volume of a cube is a³

Given a = 5 inches

→ Volume = a³

= 5³

= 5×5×5

= 125 in²

The volume of a pyramid is $\frac{1}{3} {a}^{2}h$

Given a = 5 inches , h = height of pyramid

$= > \frac{1}{3} {a}^{2} h$

$= > \frac{1}{3}(5)^{2}h$

$= > \frac{1}{3} \times 25 \times h$

$= > \frac{25}{3}h$

then,

$125 = \frac{25h}{3}$

$= > 25h = 125 \times 3$

$= > 25h = 375$

$= > h = \frac{375}{25}$

$= > h = 15$

Hence, the height of pyramid is 15 inches

7 0

2 years ago

I kinda need help nah I definitely need help

xxMikexx [17]

Answer:

<BCD = 128, <ECD = 52

Step-by-step explanation:

(3x + 5) + (x + 11) = 180

4x + 16 = 180

4x = 164

x = 41

<BCD is complimentary to <ACE which is (3x + 5). (3 * 41 + 5) = 128

<ECD is complimentary to <ACB which is (x + 11). (41 + 11) = 52.

4 0

3 years ago

What is the relationship between 2.57×104 and 2.57×10−1 ?

Shalnov [3]

Answer:

2.57×104= 267.28

2.57×10-1= 24.7

7 0

2 years ago

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Using the point-slope formula, what is the equation of the line that passes through the points (1,5) and (0, 0)?

DerKrebs [107]

Answer:

y =5x

Step-by-step explanation:

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

(5 - 0) = m(1 - 0)

5 = m(1)

5 = m

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

y - 5 = 5(x - 1)

y - 5 = 5x - 5

y = 5x -5 + 5

y = 5x

7 0

2 years ago

The equation represents an ellipse.

Tom [10]

Answer:

B) (-10, -6) and (8, -6)

Step-by-step explanation:

6 0

3 years ago

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