Question

Write the equation of the circle passing through the origin with center (– 9, –12) .

Answer 1

Answer:

$(x+9)^{2} +(y+12)^{2}=225$

Step-by-step explanation:

Remember that the center of a circle is written in (h,k) format.  So h= - 9 and k = -12.  Also, the distance between those two points is 15 units, so r = 15.

So the formula $(x-h)^{2} +(y-k)^{2}=r^{2}$

Should look like $(x+9)^{2} +(y+12)^{2}=225$