Answer:
P(A) = 0.49
Step-by-step explanation:
Given:
A and B are mutually exclusive events.
P(B) = 0.03
P(A or B) = 0.52
If two events A and B are mutually exclusive events, then there are no elements common in both the events. So, the probability of their intersection is 0.
Now, as per probability addition theorem:
P(A or B) = P(A) + P(B) + P(A and B)
For mutually exclusive events, P(A and B) = 0. So,
P(A or B) = P(A) + P(B) + 0
P(A or B) = P(A) + P(B)
Plug in the given values and solve for P(A). This gives,
0.52 = P(A) + 0.03
P(A) = 0.52 - 0.03
P(A) = 0.49
Therefore, the probability of occurrence of event A is P(A) = 0.49.
If the man stays hyradted enough then he can go 8 days without sleep
Answer: 24) d 25) d 26) d 27) a
<u>Step-by-step explanation:</u>
24)
a) a card can be red and a diamond --> Not mutually exclusive
b) a sum of 8 can include an even number (e.g. 2 + 6) --> Not mutually exclusive
c) a black card can be a Queen --> Not mutually exclusive
d) a 3 CANNOT be an even number --> Mutually exclusive!
25)
In order for event A and event B to be mutually exclusive, they cannot intersect --> P(A ∩ B) = 0
26)
P(B) = 0.34
P(A ∪ B) = 0.62
p(A ∩ B) = 0 <em>because they are mutually exclusive </em>
--> P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
0.62 = P(A) + 0.34 - 0
0.28 = P(A)
--> P(A)' = P(not A)
= 1 - P(A)
= 1 - 0.28
= 0.72
27)
hockey game = P(A) = 0.4
dance = P(B) = 0.5
hockey or dance = P(A ∪ B) = 0.8
--> hockey and dance = P(A ∩ B)
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
0.8 = 0.4 + 0.5 - P(A ∩ B)
- 0.1 = -P(A ∩ B)
0.1 = P(A ∩ B)
Answer:
The blank is 170
Step-by-step explanation:
The ratio from miles traveled to miles to go is 1:-1
520-0=520
520-100=420
520-200=320
520-350=170
520-520=0
9/5 just do the 1 times the 5 plus the 4 and thats the answer