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musickatia [10]
3 years ago
15

The first two steps in determining the solution set of the system of equations, y = x2 – 6x + 12 and y = 2x – 4, algebraically a

re shown in the table. Which represents the solution(s) of this system of equations? (4, 4) (–4, –12) (4, 4) and (–4, 12) (–4, 4) and (4, 12)
Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

(4,4)

Step-by-step explanation:

is the correct answer

Vadim26 [7]3 years ago
3 0
Y = 2x - 4....so sub in 2x - 4 for x in the other equation

y = x^2 - 6x + 12
2x - 4 = x^2 - 6x + 12
x^2 - 6x - 2x + 12 + 4 = 0
x^2 - 8x + 16 = 0
(x - 4)(x - 4) = 0

x - 4 = 0
x = 4

x - 4 = 0
x = 4

solution is (4,4)
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koban [17]

Answer:

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Step-by-step explanation:

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3 years ago
3n^2-5n-6=9 help please!
Luden [163]

Answer:

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a = 3

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n = [--5 +- sqr root(25 -4*3*-15)] / 6

n = [5 +- sqr root (25 + 180) / 6

n = [5 +-sqr root (205) ] / 6

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Step-by-step explanation:

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