What would be an example of a density independent factor that affects a population?

Refer to the picture below. This is an example of:

Sedbober [7]

Answer:

The answer is a. homologous structures

Explanation:

Homologous Structures:

Structures that have similar anatomy or similar structure but have different functions are called homologous structures.

These structures indicate shared ancestry between the animals in question. This means that the structures may be used for different functions but they are encoded by same or similar genes.

The bones in the picture perform quite different functions and they might look different from the outside but as we look closer, the bone structure and joints are similar. This shows that all of these animals evolved from a common ancestor.

5 0

2 years ago

assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

The mass of a single atom of carbon can be found by dividing the atomic mass (12.01 g) by 6.022 mc024-1.jpg 1023.

marin [14]

The mass of one atom of carbon in the correct number of significant figures is 1.99×10-²³. There are four significant figures each in both the atomic mass of carbon (12.01 g) and Avogadro's number, so the answer must also have 4 significant figures. The operation is shown below:

12.01 / (6.022x10²³) = 1.994x10₋²³

5 0

3 years ago

Read 2 more answers

Which of these activities will most likely impose an external cost? an athlete works out at a gym. a young mother pushes her bab

elixir [45]

Answer is: a secretary smokes a cigarette in a crowded break room.
External cost Is when consuming a good or servise imposes a cost to a third party. In this case, smoking affects other people in break room, causing pollution and health related problems.

3 0

3 years ago

If you could repeat the lab and make it better, what would you do differently and why?

lions [1.4K]

Answer:

The advise I will offer the next scientist about how the laboratorycan beimproved include the following

Calibration of instruments: Instruments which are used in the laboratory should be calibrated so as to reduce errors and inaccuracy during experiments.

Proper labeling of Samples : This helps to give the scientists an idea of where to find samples and to prevent making mistakes in picking the wrong one. This helps to save time and resources in the lab.

Adequate cleaning and waste disposal: Cleaning of the lab and disposal of the wastes helps to eliminate contamination of samples.

Explanation:

4 0

2 years ago