<u>Answer</u>: B. Identify the source of the active connection
<em>Any problem can be fixed only finding of the source of it. We can fix a problem in ‘n’ number of ways but it might again come back if source of it is not identified.</em>
<u>Explanation:</u>
Identify the source of the active connection is the NEXT step the team should take. It is very similar to our human body.
If the infection is coming in the body again and again and gets fixed in the treatment, the reason for come - back will be identified so that it does not <em>lead to unnecessary treatment. </em>
In a similar way, if source are identified then the problem of come-back can be avoided. <em>So option B would be the right choice.</em>
Http://www.oneandonlycampaign.org/safe_injection_practices
Answer:
listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
listString = [ ]
for i in range(14):
if listNumbers[i]%2!=0 and listNumbers[i]%5==0:
listString.append("five odd")
elif listNumbers[i]%5==0 and listNumbers[i]%2==0:
listString.append("five even")
elif listNumbers[i]%2==0:
listString.append("even")
elif listNumbers[i]%2!=0:
listString.append("odd")
print(listNumbers)
print(listString)
Explanation:
In python programming language;
- Create two lists
- The first is a list of numbers and initialize it with random values: listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
- The second list is empty and will hold the string values listString = [ ]
- Use a for loop to iterate over all the elementts in the list of numbers
- Use the modulo operator (%) to chech for multiples of particular numbers as stipulated by the question
- Use combination of if/elif statements for each condition
- Use the .append method to add the elements into the list of strings
- finially output both lists
See attached code and output
The answer to your question is,
C. Address Block
-Mabel <3
Answer:
Written in C++
#include<iostream>
using namespace std;
int main()
{
const float SALES_TAX = 0.06625;
int total = 1000;
cout<<"Total: ";
cin>>total;
float grand_total = 0;
grand_total = total + total * SALES_TAX;
if (grand_total <= 1000)
{
cout<<"Grand total is less than or equal to 1000 it is $";
printf("%.2f", grand_total);
}
else if (grand_total > 1000 && grand_total <= 2000 )
{
cout<<"Grand total is more than 1000 less than or equal to 2000 it is $";
printf("%.2f", grand_total);
}
else
{
cout<<"Grand total is greater than 2000 it is $";
printf("%.2f", grand_total);
}
cout<<"\nProgram finished!";
return 0;
}
Explanation:
<em>I've added the full source code as an attachment where I use comments to explain difficult lines</em>
