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Vesnalui [34]
3 years ago
13

Which ordered pair is a solution to the system of inequalities? y< 3x y< 5

Mathematics
2 answers:
kvv77 [185]3 years ago
5 0

(9,4)

(apex),i tried it on my test

GaryK [48]3 years ago
4 0

Answer:

<h2>Any point on the purple region.</h2>

<em>Look at the picture.</em>

Step-by-step explanation:

<, > - dotted line

≤, ≥ - solid line

<, ≤ - shaded region below a line

>, ≥ - shaded region above a line

y = 3x

for x = 0 → y = 3(0) = 0 → (0, 0)

for x = 2 → y = 3(2) = 6 → (2, 6)

y < 3x - dotted line, shaded region below the line

y = 5 - it's a horizontal line passes througth points (x, 5) <em>/x - any real number/</em>

y < 5 - dotted line, shaded region below the line

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Allushta [10]

Answer:

Step-by-step explanation:

The slope of line AB is

\frac{2-8}{3-(-3)} = \frac{-6}{6} = -1

The slope of line CD is

\frac{-1-1}{5-7} = \frac{-2}{-2} = 1

Since the slopes multiply to -1, these lines are perpendicular to one another.

8 0
3 years ago
What is y=1/2(x+3)^2+10 in standard form​
anyanavicka [17]

Answer:

Simplified equation in standard form: y=\frac{1}{4}x^{2}+12\frac{1}{4}

Original equation in standard form: y=1/2(x+3)^2+10

Step-by-step explanation:

y=\frac{1}{2}(x+3)^2+10

<u>Step 1: Distribute the </u>\frac{1}{2}<u> :</u>

<u />y=(\frac{1}{2}*x+\frac{1}{2}*3)^2+10<u />

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

<u />

<u>Step 2: Take </u>(\frac{1}{2}x+1\frac{1}{2})<u> and square it :</u>

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

y=(\frac{1}{2}x)^{2} +(1\frac{1}{2})^2+10

y=(\frac{1}{2}x*\frac{1}{2}x)+(1\frac{1}{2}*1\frac{1}{2})+10

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<u />

<u>Step 3: Add the constants:</u>

<u />y=\frac{1}{4}x^{2}+(2\frac{1}{4}+10)<u />

<u />y=\frac{1}{4}x^{2}+(12\frac{1}{4})<u />

<u />

<u>Step 4: Get rid of the parenthesis:</u>

<u />y=\frac{1}{4}x^{2}+12\frac{1}{4}<u />

<u />

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