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3 years ago

How do you evaluate 3f(2)

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

5 0

The answer should be 6f. You multiply the 3 and the 2 and then put the f at the end (:

Sergeeva-Olga [200]3 years ago

5 0

<em>6f </em> would be the answer to that equation.

HOPE THIS HELPS!!

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1. If two nonvertical lines are parallel, what do we know about their slopes? If two lines are perpendicular and neither is para

yanalaym [24]

Answer:

Two straight lines with slopes m and m' are parallel when m = m'

Two straight lines with slopes m and m' are perpendicular when m × m' = - 1.

Step-by-step explanation:

Let us assume that the two non-vertical lines in the slope-intercept form are

y = mx + c ........... (1) and

y = m'x + c' ............ (2)

If those two lines are parallel then we can say the slope of them will be the same i.e. m = m'

Now, if given two straight lines (1) and (2) are perpendicular to each other and neither of them is parallel to the axes, then we can write m × m' = - 1. (Answer)

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3 years ago

What is 0.58 as a fraction

zvonat [6]

0.58
= 58/100
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7 0

3 years ago

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Find measure of angle labeled X

trasher [3.6K]

Is it number15?
then it is
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3 years ago

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For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

------------------------------------

The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

------------------------------------

Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

--------------------------------------------------

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

3 years ago

there are four times as many cows as horses on a farm. there are twice as many horses as pigs on the farm. which list shows the

Gnesinka [82]

Well for what I understood...

Let's say...

10 Pigs in total... Horses is 2 times more than pigs so
20 Horses in total... Cow is 4 times more than horses so
80 Cows in total...

The numbers are just examples of what I sort of understood.

3 0

3 years ago