What is the sales tax of 5% on a purchase of 7.82

1 answer:

5 0

The sales tax would be $8.21 if you wanted full price because if you multiply $7.82 by 00.5 you get 0.391 to get *.21 just add $7.82 to 0.391

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Miranda drinks 12 ounces of soda per day. How many ounces of soda does she drink per year?

devlian [24]

I hope this helps u!

6 0

3 years ago

Read 2 more answers

2. Write the slope-intercept form of the equation for each graph described. Line passing through (-5, 12) and parallel to the li

Nostrana [21]

Answer: y = 2x+22

========================================================

Explanation:

The equation y = 2x+5 is in the form y = mx+b

m = 2 = slope

b = 5 = y intercept

Parallel lines have equal slopes, but different y intercepts. So the answer will be in the form y = 2x+c, where b and c are different numbers. Since b = 5, this means c must be some other number. If c = 5, then we'd have the exact same line.

Let's plug in (x,y) = (-5,12), along with the slope m = 2, and solve for c

y = mx+c

12 = 2(-5)+c

12 = -10+c

12+10 = c

22 = c

c = 22

Since m = 2 and c = 22, we go from y = mx+c to y = 2x+22

The equation of the parallel line is y = 2x+22

The graph is below.

7 0

3 years ago

Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d), one of which is co

arlik [135]

A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

$P(C) = \frac{1}{4}$

The probability of choosing wrong answer is

$P(W) = \frac{3}{4}$

Using the multiplication rule
$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

$WWC$

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

$WCW$

Or the first one is correct and the last two are wrong. This will give the arrangement,

$CWW$
.

$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

$P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}$

$P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}$

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

$P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64} \\ \\ P(One \: Correct) = \frac{27}{64}$