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Vesnalui [34]
4 years ago
6

What is the alternator-to-engine drive ratio if the

Mathematics
2 answers:
quester [9]4 years ago
4 0

Answer:

720

Step-by-step explanation:

hope it helps

azamat4 years ago
3 0

Answer:

2.25 : 1

Step-by-step explanation:

Since the ratio is 1125 rpm for the alternator: 500 rpm for the engine, find the unit rate.

1125 : 500     Divide both sides by 500

2.25 : 1         For every turn of the engine, there are 2.25 turns of the alternator.

If this answer is correct, please make me Brainliest!

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In ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. What is the value of the sine of ∠R to the nearest hundreth
irina [24]

We have been given that in ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. We are asked to find the value of sine of ∠R to the nearest hundreth.

First of all, we will draw a right triangle using our given information.  

We know that sine relates opposite side of right triangle to hypotenuse.

We can see that side SR is hypotenuse and TS is opposite side to angle R.

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Upon rounding to nearest hundredth, we will get:

\sin(\angle R)\approx 1.97

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