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Vesnalui [34]
3 years ago
6

What is the alternator-to-engine drive ratio if the

Mathematics
2 answers:
quester [9]3 years ago
4 0

Answer:

720

Step-by-step explanation:

hope it helps

azamat3 years ago
3 0

Answer:

2.25 : 1

Step-by-step explanation:

Since the ratio is 1125 rpm for the alternator: 500 rpm for the engine, find the unit rate.

1125 : 500     Divide both sides by 500

2.25 : 1         For every turn of the engine, there are 2.25 turns of the alternator.

If this answer is correct, please make me Brainliest!

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The standard form of -36/-216
GrogVix [38]

Answer:

\frac{1}{6}

Step-by-step explanation:

\frac{-36}{-216} \\=\frac{36}{216} \\=\frac{1}{6}

5 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? Put your answer in slope-intercept form.
Scrat [10]

Answer:

  a.  y = 2/5x + 1/5

Step-by-step explanation:

In point-slope form, the equation of a line with slope m through point (h, k) can be written

  y = m(x -h) +k

Then a line with slope 2/5 through the point (-3, -1) will have point-slope equation ...

  y = (2/5)(x +3) -1

This can be simplified to the desired form:

  y = 2/5x +6/5 -1 . . . . . . eliminate parentheses; next, collect terms

  y = 2/5x + 1/5

8 0
3 years ago
Read 2 more answers
9 – 2x = 19<br> What is x
iren2701 [21]

9-2x=19

or,-2x=19-9

or,-2x=10

or,x=10/-2

therefore,

x=-5

6 0
3 years ago
Read 2 more answers
If (8^9)p = 8^16 what's the value of p?
monitta

Answer:

p  = {8}^{7}

Step-by-step explanation:

(8^9)p = 8^{16 } \\  \\ p =  \frac{8^{16 } }{8^{9 } }  \\  \\  p =  {8}^{16 - 9}  \\  \\  \huge \red{ \boxed{p  = {8}^{7} }}

8 0
2 years ago
Need the answer for this thanks. I got C but that is incorrect​. Please show work thanks! ​
natulia [17]

Answer:

Step-by-step explanation:

a: Wrong. The first thing that you have to notice is that the sum goes to infinity. If you want k=4 to be the last condition, then take out the 3 dots.

b: That's the answer.

c: wrong. You get a real mess when you let set k = 0. Try it on your calculator.

1 ÷ 0 = Watch carefully as your calculator mentally melts down.

d: wrong. It's just not right. The highest power is k^2. There is no way to get k^3

8 0
3 years ago
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