<h3>20 subtracted from three times a number is 6 more than the number. Then the number is 13</h3>
<em><u>Solution:</u></em>
<em><u>Given statement is:</u></em>
20 subtracted from three times a number is 6 more than the number
We can translate the sentence into algebraic expression
Let "a" be the unknown number
Then,
20 subtracted from three times "a" is 6 more than "a"
Which means,
3a - 20 = 6 + a
3a - a = 6 + 20
2a = 26
Divide both sides by 2
a = 13
Thus the number is 13
The total number of significant figures in C is 5 because when the two numbers are multiplied then the result obtained has the least significant figure.
Given :
- Lillian multiplies two numbers.
- A has five significant figures and two decimal places and B has six significant figures and four decimal places.
The following steps can be used in order to determine the total number of significant figures of C:
Step 1 - According to the given data, 'A' has five significant figures and two decimal places and 'B' has six significant figures and four decimal places.
Step 2 - It is also given that C is equal to A times B.
Step 3 - So, the total number of significant figures in C is 5 because when the two numbers are multiplied then the result obtained has the least significant figure.
Therefore, the correct option is C).
For more information, refer to the link given below:
brainly.com/question/11904364
Answer:
(t+1)(t^2+1)
Step-by-step explanation:
t^3+t^2+t+1
(t+1)(t^2+1)
Answer:
D
Step-by-step explanation:
Just go with it I took the class
