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3 years ago

The ratio of the corresponding side lengths is 10:7 What is the ratio of the areas?

1 answer:

4 0

100 to 49. Because area is units squared, and it is finding by multiplying the side lengths, you would simply square the ratio.

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Are the figures similar?

pychu [463]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student

SashulF [63]

Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

Verify the midpoint of each student

student 1

we have the endpoints

(-9,0) and (11,-8)

substitute in the formula

$M(\frac{-9+11}{2},\frac{0-8}{2})$

$M(1,-4)$

The midpoint is not (-1,4)

student 2

we have the endpoints

(-6,-1) and (4,-7)

substitute in the formula

$M(\frac{-6+4}{2},\frac{-1-7}{2})$

$M(-1,-4)$

The midpoint is not (-1,4)

student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

$M(\frac{-5+3}{2},\frac{2+6}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

$M(\frac{-3+5}{2},\frac{10-2}{2})$

$M(1,4)$

The midpoint is not (-1,4)

student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

$M(\frac{0-2}{2},\frac{-3+11}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

therefore

Student 3 and student 5

3 0

3 years ago

What is the surface area of a square pyramid that has an 8 cm base length and triangular faces that are 14 cm tall? square centi

tatiyna

It's around 296.96 cm^2

good luck

7 0

2 years ago

Read 2 more answers

Quick pls!! my math grade is at a B! I need to raise it.

Leokris [45]

I don’t know but I think it should be -04 I assume don’t know

5 0

1 year ago

What is the slope of the line?

12345 [234]

You can find the slope using the following formula:

$\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ where\colon \\ (x1,y1)=(0,2) \\ (x2,y2)=(1,0) \\ m=\frac{0-2}{1-0}=\frac{-2}{1}=-2 \end{gathered}$

8 0

11 months ago