Answer:
g = ±2h
Step-by-step explanation:
4g^2 -1= 16h^2 -1
Add 1 to each side
4g^2 -1+1= 16h^2 -1+1
4g^2 = 16h^2
Divide each side by 4
4/4g^2 = 16/4h^2
g^2 = 4 h^2
Take the square root of each side
sqrt(g^2) = ±sqrt(4h^2)
g = ±sqrt(4h^2)
g = ±2h
Answer:
0.25feet
Step-by-step explanation:
The equation is not well written. Let the equation of the height be modelled as;
h = -16d²+8d+4
The velocity of the ball is zero at its maximum height.
Velocity = change in displacement/time
v = dh/dd
Differentiate
v = -32d+8
Since dh/dd = v = 0
0 = -32d+8
Add 32d to both sides
0+32d = 8
32d = 8
Divide both sides by 32
32d/32 = 8/32
d = 1/4
d = 0.25feet
Hence the maximum height of the tennis ball is 0.25feet
Note that the modeled equation was assumed. You can apply the same calculation to any equation given
Answer:
false
Step-by-step explanation:
Answer:
I subtract it the porportiin
Step-by-step explanation:
And what year r u in ???? So then I'm help u and understand
Answer:
simplify it further
you will get f(x) = x^(2) + 32
