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andreyandreev [35.5K]
3 years ago
6

True or false? A circle could be circumscribed about the quadrilateral below

Mathematics
2 answers:
tatyana61 [14]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

A circle can be circumscribed around the four vertices of a quadrilateral if and only if,

both pair of opposite angles inscribed in the quadrilateral are supplementary to each other. By supplementary to each other we mean that their sum is equal to 180°.

In this case we have opposite interior angles supplementary to each other hence we can circumscribe a circle around it. Such Quadrilateral are called cyclic quadrilateral.

ArbitrLikvidat [17]3 years ago
3 0

Answer:

true

Step-by-step explanation:

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25 in 1/2minute
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25*10=250

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14

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Bryan is observing the velocity of a cyclist at different times. After four hours, the velocity of the cyclist is 15 km/h. After
myrzilka [38]

Part A.

What we can do to solve this problem is to assume that the acceleration of Bryan is constant so that the velocity function is linear. The standard form of a linear function is in the form:

y = m x + b

or in this case:

v = m t + b

where v is velocity and t is time, b is the y –intercept of the equation

The slope m can be calculated by:

m = (v2 – v1) / (t2 – t1)

m = (12 – 15) / (7 – 4)

m = -1

Since slope is negative therefore this means the cyclist are constantly decelerating. The equation then becomes:

v = - t + b

Now finding for b by plugging in any data pair:

15 = - (4) + b

b = 19

So the complete equation is:

v = - t + 19

This means that the initial velocity of the cyclists at t = 0 is 19 km / h.

 

Part B. What we can do to graph the equation is to calculate for the values of v from t = 0 to 12, then plot all these values in the Cartesian plane then connect the dots.

6 0
4 years ago
5(x+2)=6x+3x-14 please solve
zavuch27 [327]

Answer:

5(x+2)=6x+3x−14

Step 1: Simplify both sides of the equation.

5(x+2)=6x+3x−14

(5)(x)+(5)(2)=6x+3x+−14(Distribute)

5x+10=6x+3x+−14

5x+10=(6x+3x)+(−14)(Combine Like Terms)

5x+10=9x+−14

5x+10=9x−14

Step 2: Subtract 9x from both sides.

5x+10−9x=9x−14−9x

−4x+10=−14

Step 3: Subtract 10 from both sides.

−4x+10−10=−14−10

−4x=−24

Step 4: Divide both sides by -4.

−4x

−4

=

−24

−4

x=6

Answer:

x=6

7 0
3 years ago
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