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serious [3.7K]
3 years ago
12

I need help ASAP please...............

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

Google it please!!!!!!!!!

Mazyrski [523]3 years ago
7 0

Answer:

Step-by-step explanation:

C is the answer

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What is the discriminant: 2x^2 + 3x + 10=0
ohaa [14]
The discriminant of a quadratic equation is:

b^2-4ac

Plug in the values. 

3^2-4(2)(10)

=9-80

=-71 

Since the discriminant is negative, you can tell that the quadratic has no real solutions. 

Hope that helped!

~Cam943, Moderator
6 0
3 years ago
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Find the formula for df^-1/dx.<br><br> f(x)=(7-x)^3
klio [65]
Here is the equation to solve the problem above:

f(x) = (7-x)^3
y = (7-x)^3

switch y and x
 x = (7 - y)^3
 
third root of x = 7 - y
-y = 3rootx - 7
 
so:<span><span>f′(x)=3^<span>√x</span>−7</span></span>
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3 years ago
What 1,055 to the nearest tenth
Burka [1]
1,060 hope this helped !
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PLEASE HELP ME IM BEING TIMEDD
JulsSmile [24]
10 rows because that's right
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Math Questions :3 thank uu &lt;3
coldgirl [10]
14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
8 0
3 years ago
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