What is the long division Answer for 8639 ÷ 5?

Percentage homeworkkk… (Middle School)

weeeeeb [17]

Answer:

75% for number 2 i think number 3 is 70%

3 0

2 years ago

Read 2 more answers

What is the Area of the Trapezoid GHIK?

tresset_1 [31]

Answer:

The area of the trapezoid is 56 sq ft

6 0

3 years ago

Activity paper to answer

PIT_PIT [208]

Answer:

1.

a) 5cm

b) 16cm

c) 25cm

d) 124cm

2.

a) 4m

b) 6m

c) 10m

d) 26m

3.

a) 2km

b) 4km

c) 11km

d) 28km

Step-by-step explanation:

When you have a number and it tells you to round it to the nearest cm (m, km etc.), it means you just have to make it a whole number (integer) instead of a decimal by rounding it up or down.

To tell whether you round up or down, you look at the number after the decimal place and if it is under 5, you round down but if it is 5-9 you round up.

For example,

If we had 20.3 (not one of the questions) you would round it down to 20 because the 3 after the decimal place is smaller than 5.

However, if we had 24.7 you would have to round it up because the 7 is from 5-9.

Hope this helps :)

5 0

2 years ago

What property is shown?

svetoff [14.1K]

Zero Property of Multiplication hope this helps

3 0

2 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

2 years ago