Select the assumption necessary to start an indirect proof of the statement.

When (3,-2) is reflected across the x-axis the resulting image point is:

FromTheMoon [43]

Answer:

(3,2)

Step-by-step explanation:

when reflecting across the x axis the y value becomes - while the x value stays the same

4 0

3 years ago

How to find the common denominator of two numbers?

Snowcat [4.5K]

Find the number that both can be divided by i.e. the common denominator of 56/8 is 8 because 56 is divisible by 8 and 8 is also divisible by 8.
so by finding the common denominator and dividing the fraction, the equation would look like this: 7/1

3 0

3 years ago

What are all of the rational zeros of the function g(x) = x^4- x^3+ 4x^2- 4x?

Darya [45]

Yo sup??

We can solve this questions by trying option verification.

We observe that 0 is common among all the options so 0 has to be a zero of the function.

when x=1

g(1)=1-1+4-4=0

Therefore 1 is also a zero of the function.

Since 1 is not there is option 2 and 3, hence our answer is either option 1 or 4

when x=2

g(2)=16-8+16-8=0

Therefore 2 is also a zero of the function.

Hence the correct answer is option D ie 0,1,2

Hope this helps.

6 0

3 years ago

Elaine has a piece of wire that is 2.16 m long. John has a piece of wire that is 2.061 m long. Who is piece of wire is longer? H

lesya [120]

Elaine's would be because.16 is closer to being a whole than .016

4 0

3 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

2 years ago

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