First, subtract 5 from both sides, leaving you with 5
![x^{2}](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20)
- 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)
x=-b +/- √b²-4ac / 2a
x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)
x= 30 +/- √1000 / 10
x = 3 +/- √10
I think x= 65 I hope this helped
Answer:
EF = 20 cm
Step-by-step explanation:
Here, we want to find the length of EF
To do this, we use the principle of similar triangles
The similar triangles we are considering here will be ;
FEA and FBD
when two triangles are similar, the ratio of their corresponding sides are equal
Let us calculate DC first
we can use Pythagoras’ theorem here and it is that the square of the hypotenuse equals the sum of the square of the two other sides
Using the triangle EDC
15^2 = 12^2 + DC^2
DC^2 = 225-144
DC^2 = 81
DC = 9
So the entire length of BD is 9 + 12 = 21 cm
Thus, we have it that;
Let EF be x
so DF = 15 + x
Hence;
BD/DF = AE/EF
21/15+x = 12/x
21x = 12(15 + x)
21x = 180 + 12x
21x-12x = 180
9x = 180
x = 180/9
x = 20 cm
EF = 20 cm
Answer:
tan∠E=1/3
Step-by-step explanation:
Tangent or opposite/adjacent of angle E is segment HF/3 to solve for HF you can use sine of H opposite over hypotenuse or √8/HF=sin45°. Rearranging the equation you get √8/sin45°=HF and sin45°= 2√2 so √8/2√2=1 HF=1 now you know that tan(∠E)=1/3.
Equation in slope-intercept form is y = 2x - 6
Step-by-step explanation:
- Step 1: Given slope of the line, m = 2. Form an equation y = mx + b
⇒ y = 2x + b ---- (1)
- Step 2: The line passes through the point (4,2). So it will satisfy the equation. Find b by substituting x = 4 and y = 2.
⇒ 2 = 2 × 4 + b = 8 + b
⇒ b = -6
- Step 3: Form the slope-intercept equation.
⇒ y = 2x - 6