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natali 33 [55]
3 years ago
10

How is the execution speed of machine language compared to that of high-level languages? The execution speed of machine language

is ____ than the execution speed of other languages.
Computers and Technology
2 answers:
Mandarinka [93]3 years ago
8 0

Answer: Faster

Explanation:

Execution speed is defined as speed of carrying out and completing a task or command or instruction in a cycle. Execution speed of machine or assembly language is rapid among all other language.

Instructions are received from central processing unit (CPU) directly to execute it , thus fastest execution is processed .

As for high level language and other languages,they are converted into machine language so that it can be understood by system to execute instruction.

Alik [6]3 years ago
7 0

The execution speed of machine language is faster than the execution speed of other languages. Machine or assembly language will execute the fastest as compared to high-level languages. No other language can execute faster than Machine language since instructions are directed straight to the CPU. Other high-level languages often add some non-zero amount of overhead to the execution time, thus, causing some delay.

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Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither.
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Question:

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Answer:

Written in Python

listlent = int(input("Length of List: "))

mylist = []

mylist.append(listlent)

for i in range(listlent):

    num = int(input(": "))

    mylist.append(num)

<em>    </em>

evens = 0

odds = 0

for i in range(1,listlent+1):

    if mylist[i]%2==0:

         evens=evens+1

    else:

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Explanation:

This prompts user for length of the list

listlent = int(input("Length of List: "))

This initializes an empty list

mylist = []

The following iteration reads the list items from the user

<em>mylist.append(listlent)</em>

<em>for i in range(listlent):</em>

<em>     num = int(input(": "))</em>

<em>     mylist.append(num)</em>

   

The next two lines initialize even and odd to 0, respectively

<em>evens = 0</em>

<em>odds = 0</em>

<em />

The following iteration if a list item is even or odd

<em>for i in range(1,listlent+1):</em>

<em>     if mylist[i]%2==0:</em>

<em>          evens=evens+1</em>

<em>     else:</em>

<em>          odds=odds+1</em>

This checks and prints if all list items is odd        

<em>if(evens == 0 and odds != 0):</em>

<em>     print("All Odds")</em>

This checks and prints if all list items is even        

<em>elif(evens != 0 and odds == 0):</em>

<em>     print("All Even")</em>

This checks and prints if all list items is neither even nor odd

<em>else:</em>

<em>     print("Neither")</em>

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