Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / ~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
Code is provided in the attachment form
Explanation:
Vector Multiplication code:
Vector_multiplication.c file contains C code.
See attachment no 1 attached below
Classification of Algorithm: For creating elements in vector c of size n, number of scalar multiplications is equal to n. The size of original two vectors scales directly with the number of operations. Hence, it is classified as O(n).
